show the cases the comments were describing

fmt-c-writer.scm

@@ -381,11 +381,13 @@ forms, and what remains."
       ;; are not part of it: ((* const char)), (int)
       (walk-type (maybe-unwrap-type arg))))
 
-;;; A parameter reaches fmt-c as `(type name)' and nothing else: it
-;;; reads the name out with `cadr', so a nameless one is the type and
-;;; an explicit #f. Handing it the bare type instead made it read the
-;;; type's own second word as the name -- `(* const char)' lost its
-;;; star -- and a one-word type had no second word to read at all.
+;;; fmt-c reads a parameter as `(type name)', taking the name with
+;;; `cadr'. A nameless one is the type and an explicit #f:
+;;;
+;;;   (* const char)       ->  const char     the star read as the name
+;;;   ((* const char) #f)  ->  const char *
+;;;   (int)                ->  (cadr) error
+;;;   (int #f)             ->  int
 (define (walk-arglist form)
   ;; E.g.:
   ;; ((float) (int) (const char) (* const char) (¤ (* const struct res) 32))