Files
sex/types.scm
alex-eg 97ef62b7f4 resolve typedefs in get-fields and map-fields
Now these macro helpers take in account the possibility of typedefing
one type to another, and correctly find the one intended
2026-09-16 17:07:21 +03:00

158 lines
5.6 KiB
Scheme

;;; The type database.
;;;
;;; Every named aggregate, typedef and define the semantic engine
;;; walks past is recorded here, so that macros (or other forms) can
;;; ask what a type is made of. That is what lets a macro generate
;;; code from a struct's fields given nothing but its name.
;;;
;;; Entries are filled in as toplevel forms are processed, in order, so
;;; a type has to be declared before the macro that asks about it.
(import
scheme
(scheme base)
(chicken base)
srfi-1
srfi-69)
(define +type-db+ (make-hash-table))
(define (strip-pub form)
(if (eq? (car form) 'pub) (cdr form) form))
(define (comment-form? f)
(and (pair? f) (eq? (car f) 'comment)))
;;; Fields are written with the type last and one or more names before
;;; it, so ((x y int) (p (* char))) describes three fields. Flatten that
;;; into one (name type) per field, which is what a caller wants.
(define (normalize-fields fields)
(append-map
(lambda (field)
(if (comment-form? field)
(list)
(let ((type (last field))
(names (drop-right field 1)))
(map (lambda (name) (list name type)) names))))
(remove comment-form? fields)))
;;; ([pub] struct name (fields ...) . attrs)
(define (aggregate-fields form)
(let ((f (strip-pub form)))
(if (and (pair? (cddr f)) (list? (caddr f)))
(caddr f)
(list))))
(define (add-struct name form)
(hash-table-set! +type-db+ name
(list 'struct name (normalize-fields (aggregate-fields form)))))
(define (add-union name form)
(hash-table-set! +type-db+ name
(list 'union name (normalize-fields (aggregate-fields form)))))
;;; ([pub] enum name (value ...))
(define (add-enum name form)
(let ((f (strip-pub form)))
(hash-table-set! +type-db+ name
(list 'enum name (if (and (pair? (cddr f)) (list? (caddr f)))
(caddr f)
(list))))))
;;; ([pub] typedef new-name target)
(define (add-typedef name form)
(hash-table-set! +type-db+ name
(list 'typedef name (last (strip-pub form)))))
;;; (define name value ...) -- a C #define, kept so a macro can read a
;;; compile-time constant rather than re-parse the source.
(define (add-define name form)
(hash-table-set! +type-db+ name
(list 'define name (cddr (strip-pub form)))))
(define (get-type-info name)
(hash-table-ref/default +type-db+ name #f))
;;; ((name type) ...) for a struct or union, #f for anything else --
;;; including a name that was never declared. Callers give the better
;;; error, since they know what they wanted it for.
;;;
;;; A typedef is followed to what it stands for, so reflection over an
;;; alias works exactly as it does over the name it aliases.
(define (get-fields name)
(let ((info (resolve-type-info name)))
(and info
(memq (car info) '(struct union))
(caddr info))))
;;; Follow a typedef chain to the name it stands for. #f if NAME is
;;; not a typedef. A typedef that leads back to itself stops rather
;;; than spinning: nothing prevents one from being written.
(define (get-underlying-type name)
(let follow ((name name) (seen (list)))
(and (not (member name seen))
(let ((info (get-type-info name)))
(and info
(eq? (car info) 'typedef)
(let ((target (caddr info)))
(or (and (symbol? target) (follow target (cons name seen)))
target)))))))
;;; The declaration NAME ultimately names. For a typedef that is the
;;; entry of whatever it stands for, and for anything else it is
;;; NAME's own info.
(define (resolve-type-info name)
(let ((info (get-type-info name)))
(and info
(if (eq? (car info) 'typedef)
(let* ((target (get-underlying-type name))
(tag (cond ((symbol? target) target)
((and (pair? target)
(pair? (cdr target))
(symbol? (cadr target)))
(cadr target))
(else #f))))
(and tag (get-type-info tag)))
info))))
;;; Type matcher macro
;;; (type-match type
;;; (int ...)
;;; ((* const char) ...)
;;; ([int 10] ...)
;;; (else ...))
;;;
;;; A type is a form, not an atom, so this compares with equal? rather
;;; than dispatching like `case'. Patterns are literal types and are not
;;; evaluated; `else' is optional and the whole thing is #f when nothing
;;; matches and there is no else.
(define-syntax type-match
(syntax-rules (else)
((_ type) #f)
((_ type (else body ...)) (begin body ...))
((_ type (pattern body ...) clause ...)
(if (equal? type 'pattern)
(begin body ...)
(type-match type clause ...)))))
;;; Map function to each field/value of a structure/union/enum
;;; For enums, field-type is the type of the enum (since C 23)
;;; (map-fields type-name
;;; (lambda (field-name field-type) ...))
;;;
;;; Returns #f if nothing of that name was declared
(define (map-fields struct-union-enum fn)
(let ((info (resolve-type-info struct-union-enum)))
(and info
(case (car info)
((struct union)
(map (lambda (field) (fn (car field) (cadr field)))
(caddr info)))
;; An enumerator's type is the enum itself -- named as it was
;; declared, since `enum some-typedef' is not a C type.
((enum)
(let ((type (list 'enum (cadr info))))
(map (lambda (value) (fn value type))
(caddr info))))
(else #f)))))