implement closures

This commit is contained in:
2026-09-29 21:07:16 +03:00
parent 1084b7d266
commit 8a3f51e833
10 changed files with 622 additions and 41 deletions

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@@ -270,4 +270,59 @@ compiles."
"_Static_assert(sizeof(int) == 4, \"int is four bytes\")"))
(test-assert "and not the header macro"
(not (emits? (in-fn "(static-assert (== (sizeof int) 4) \"x\")")
"static_assert(")))))
"static_assert("))))
;; A closure is a code pointer beside its captures. The struct is
;; named from the signature, so separate translation units agree on
;; it, and calling one goes through `code' with `env' passed first.
;;
;; A closure struct, and the helper its calls go through, are each
;; emitted once per signature; the registries deciding that are
;; compile-time state like the type databases, and outlive a single
;; `sex->c' here. So every case below that looks for a *definition*
;; uses a signature of its own -- cases looking at a call site can
;; share one.
(test-group "closures"
(test-assert "the type becomes a struct named for its signature"
(emits? "(fn f ((c (closure ((int)) int))) int (return (c 1)))"
"struct ƛint_int"))
;; The environment is one shared union, declared in the prelude --
;; its layout is part of the ABI two units agree on, so it cannot
;; depend on what either file contains. `sex->c' has no prelude, so
;; what is visible here is the member
(test-assert "whose environment is the shared union"
(emits? "(fn f ((c (closure ((float)) int))) int (return (c 1.0)))"
"union ƛenv env;"))
;; The receiver goes through a helper rather than being written
;; out twice, so that `[table (++ i)]' evaluates its index once,
;; exactly as it would for an array of function pointers
(test-assert "a call passes the receiver to a helper"
(emits? "(fn f ((c (closure ((int)) int))) int (return (c 1)))"
"ƛint_int_call(c, 1)"))
(test-assert "and the helper is what dereferences it"
(emits? "(fn f ((c (closure ((long)) int))) int (return (c 1)))"
"ƛc.code(&ƛc.env, ƛa0)"))
(test-assert "a subscript receiver is evaluated once"
(emits? "(fn f ((t (¤ (closure ((int)) int) 4)) (i int)) int (return ((¤ t (++ i)) 1)))"
"ƛint_int_call(t[++i], 1)"))
(test-assert "so is a member receiver"
(emits? "(struct h ((cb (closure ((int)) int))))
(fn f ((s (struct h))) int (return ((. s cb) 1)))"
"ƛint_int_call(s.cb, 1)"))
(test-assert "a captured name is rebound in the lifted body"
(emits? "(fn f ((n int)) (closure ((char)) int) (return (closure ((x char)) int (n) (return n))))"
"int n = ƛcaptures->n;"))
(test-assert "captures are checked against the environment"
(emits? "(fn f ((n int)) (closure ((short)) int) (return (closure ((x short)) int (n) (return n))))"
"_Static_assert(sizeof(struct"))
;; A closure over nothing has no record to point at, and C has no
;; empty struct to declare for it
(test-assert "no captures means no capture record"
(not (emits? "(fn f () (closure () int) (return (closure () int () (return 7))))"
"_captures {")))
;; The receiver is written twice, so a name used as an argument
;; must not be mistaken for a call of its own
(test-assert "a closure passed as an argument stays a value"
(emits? "(fn g ((c (closure ((int)) int))) int (return 0))
(fn f ((c (closure ((int)) int))) int (return (g c)))"
"g(c)"))))

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@@ -10,14 +10,17 @@
#
# It also checks what only a second translation unit can check: that an
# imported type reaches the type database, by expanding a macro that
# reads the imported struct's fields.
# reads the imported struct's fields; and that a closure type crossing
# the boundary works both ways -- one built in the module and called
# here, one built here and called there, through a code pointer that is
# static in the other object.
#
# The public forms carry comments in their headers, which the reduction
# to a prototype and to an extern both have to look past.
SEXC ?= ../../sexc
EXPECTED = hello, world\nhello, sex\n2 greetings\ntext times \ntext times \nmood 1
EXPECTED = hello, world\nhello, sex\n2 greetings\ntext times \ntext times \nmood 1\nclosure 15 21 201
check:
@$(SEXC) greet.sex -c -o greet.o

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@@ -26,4 +26,11 @@
(printf "\n")
(var m (enum mood) grumpy)
(printf "mood %d\n" m)
(var add-10 (closure ((int)) int) (make-adder 10))
(printf "closure %d %d" (add-10 5) (apply-twice add-10 1))
(var base int 100)
(var here (closure ((int)) int)
(closure ((x int)) int (base) (return (+ base x))))
(printf " %d\n" (apply-twice here 1))
(return 0))

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@@ -35,6 +35,19 @@
(++ greet-count)
(printf "hello, %s\n" name))
;;; A closure type crossing the boundary. Both units generate the
;;; struct for this signature independently, so they have to agree on
;;; its tag and its layout, or the value is passed wrong and nothing
;;; says so.
(pub fn make-adder ((n int)) (closure ((int)) int)
(return (closure ((b int)) int (n)
(return (+ n b)))))
;;; The other direction: a closure built by the importer, whose code
;;; pointer is static in *its* object, called from here
(pub fn apply-twice ((f (closure ((int)) int)) (x int)) int
(return (f (f x))))
;;; Not `pub': invisible to importers, and static in the generated C.
(fn unused-helper () void
(printf "private\n"))

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@@ -0,0 +1,80 @@
(input)
(output "Adders: 15 25"
"Two captures: 47"
"No captures: 7"
"Through a parameter: 110"
"From an array: 1 2 3"
"Index evaluated once: 21 i 1"
"Through a struct member: 8"
"Nested: 33")
(return 0)
;;; A closure is a code pointer beside its captures, so what this
;;; checks is that the captures survive the lifting -- that two
;;; closures of one shape keep their own environments, that a closure
;;; outlives the call that built it, and that calling one through a
;;; parameter, an array element or a struct member resolves the same
;;; way as through a local.
;;;
;;; A receiver is also an ordinary expression: `[table (++ i)]' has to
;;; evaluate its index exactly once, the way it would for an array of
;;; function pointers.
(include stdio.h)
(fn make-adder ((n int)) (closure ((int)) int)
(return (closure ((b int)) int (n)
(return (+ n b)))))
(fn make-affine ((k int) (b int)) (closure ((int)) int)
(return (closure ((x int)) int (k b)
(return (+ (* k x) b)))))
(fn make-const-7 () (closure () int)
(return (closure () int ()
(return 7))))
;;; A closure arriving as a parameter: its type is written, so the call
;;; resolves without knowing where it came from
(fn apply-twice ((f (closure ((int)) int)) (x int)) int
(return (f (f x))))
(struct handlers ((on-tick (closure ((int)) int))))
(pub fn main () int
(var add-10 (closure ((int)) int) (make-adder 10))
(var add-20 (closure ((int)) int) (make-adder 20))
(printf "Adders: %d %d\n" (add-10 5) (add-20 5))
(var affine (closure ((int)) int) (make-affine 5 2))
(printf "Two captures: %d\n" (affine 9))
(var seven (closure () int) (make-const-7))
(printf "No captures: %d\n" (seven))
(printf "Through a parameter: %d\n" (apply-twice (make-adder 50) 10))
(var table (¤ (closure ((int)) int) 3))
(var i int 0)
(for (= i 0) (< i 3) (++ i)
(= (¤ table i) (make-adder i)))
(printf "From an array: %d %d %d\n"
((¤ table 0) 1) ((¤ table 1) 1) ((¤ table 2) 1))
;; the index must be evaluated once, so `i' ends at 1 and not 2 --
;; read in a separate statement, since reading and bumping it in one
;; printf would be unsequenced whatever the closure did
(= i 0)
(var once int ([table (++ i)] 20))
(printf "Index evaluated once: %d i %d\n" once i)
(var h (struct handlers) #((struct handlers) : .on-tick (make-adder 5)))
(printf "Through a struct member: %d\n" ((. h on-tick) 3))
;; a closure built inside a closure, capturing that one's capture
(var outer (closure ((int)) int)
(closure ((x int)) int ()
(var inner (closure ((int)) int) (make-adder x))
(return (inner 3))))
(printf "Nested: %d\n" (outer 30))
(return 0))

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@@ -0,0 +1,55 @@
(input)
(output "direct: 120"
"fac: 120 3628800"
"fib: 55 6765")
(return 0)
;;; A fixed point built out of closures, which is the hardest thing to
;;; ask of them: recursion with no recursive function anywhere, only
;;; self-application.
;;;
;;; Self-application needs `x x' and so a recursive type, which is
;;; spelled here by routing it through a named struct whose field is a
;;; closure whose own signature mentions that struct. The generated
;;; closure struct is written before `struct rec' is, so this only
;;; compiles because a forward declaration is emitted ahead of both.
;;;
;;; Note what `fix' captures: a *pointer* to the knot, not the knot. A
;;; closure is a code pointer beside N bytes of environment, so
;;; capturing one by value would need N >= 8 + N. No budget makes that
;;; true, and the static assertion says so rather than letting it
;;; corrupt anything.
(include stdio.h)
(struct rec ((f (closure (((* (struct rec))) (int)) int))))
;;; Takes a step that expects itself, returns an ordinary closure with
;;; the self-application hidden inside
(fn fix ((step (* (struct rec)))) (closure ((int)) int)
(return (closure ((n int)) int (step)
(return ((-> step f) step n)))))
(pub fn main () int
(var fac-knot (struct rec))
(= (. fac-knot f)
(closure ((self (* (struct rec))) (n int)) int ()
(if (<= n 1) (return 1))
(return (* n ((-> self f) self (- n 1))))))
;; the knot applied to itself directly, without fix
(printf "direct: %d\n" ((. fac-knot f) (& fac-knot) 5))
(var fib-knot (struct rec))
(= (. fib-knot f)
(closure ((self (* (struct rec))) (n int)) int ()
(if (< n 2) (return n))
(return (+ ((-> self f) self (- n 1))
((-> self f) self (- n 2))))))
;; one combinator, two different recursions
(var fac (closure ((int)) int) (fix (& fac-knot)))
(var fib (closure ((int)) int) (fix (& fib-knot)))
(printf "fac: %d %d\n" (fac 5) (fac 10))
(printf "fib: %d %d\n" (fib 10) (fib 20))
(return 0))